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Question
Determine the point on the graph of the linear equation 2x + 5y = 19, whose ordinate is `1 1/2` times its abscissa.
Solution
Given: 2x + 5y = 19 ...(i)
Ordinate is `1 1/2` times its abscissa
⇒ `y = 1 1/2 x = 3/2 x`
Putting `y = 3/2x` in equation (i)
We have `2x + 5 3/2x = 19`
⇒ `19/2x = 19`
⇒ x = 2
Putting x = 2 in equation (i)
We have 2 × 2 + 5y = 19
`y = (19 - 4)/5 = 3`
Therefore, point (2, 3) is the required solution.
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