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प्रश्न
Differentiate `cos^-1((3cosx-2sinx)/sqrt13)` w. r. t. x.
उत्तर
`Let y=cos^-1((3cosx-2sinx)/sqrt13) `
` =cos^-1(3/sqrt13cosx-2/sqrt13sinx)`
`Put cosA=3/sqrt13`
`sinA=sqrt(1-9/13)=2/sqrt13`
`y=cos^-1[cosAcosx-sinAsinx]`
`y=cos^-1[cos(A+x)]`
y = A + x, where A is a constant
`dy/dx=d/dx(A+x)=1`
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