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Discuss the continuity and differentiability of f(x) = (2x + 3) |2x + 3| at x = -32 - Mathematics and Statistics

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प्रश्न

Discuss the continuity and differentiability of f(x) = (2x + 3) |2x + 3| at x = `- 3/2`

योग

उत्तर

If `x ≥ -3/2`, |2x + 3| = 2x + 3 and if `x < -3/2`, |2x + 3| = − (2x + 3)

∴ f(x) `{:(= (2x + 3)^2"," , "for"  x ≥ - 3/2),(= -(2x + 3)^2"," , "for"  x < - 3/2):}`

`"R" "f'"(-3/2) =  lim_("h" -> 0) ("f"(- 3/2 + "h") - "f"(-3/2))/"h"`

= `lim_("h" -> 0) ([2(- 3/2 + "h") + 3]^2 - [2(- 3/2) + 3]^2)/"h"    ...[because "f"(x) = (2x + 3)^2","  "for"  x ≥ - 3/2]`

= `lim_("h" -> 0) ([(-3 + 2"h") + 3]^2 - 0)/"h"`

= `lim_("h" -> 0) (4"h"^2)/"h"`

= `lim_("h" -> 0) (4"h")`   ...[∵ h → 0 ∴ h ≠ 0]

= 0

Similarly, `"L" "f'"(- 3/2)` = 0

∴ `"R""f'"(- 3/2) = "L" "f'"(- 3/2)` = 0

∴ f is differentiable at x = `- 3/2` and hence continuous at x = `-3/2`.

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Definition of Derivative and Differentiability
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differentiation - Exercise 9.1 [पृष्ठ १८८]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board
अध्याय 9 Differentiation
Exercise 9.1 | Q 5. (ii) | पृष्ठ १८८

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