Question

Divide the given polynomial by the given monomial.

8(x³y²z² + x²y³z² + x²y²z³) ÷ 4x²y²z²

Answer 1

8(x³y²z² + x²y³z² + x²y²z³) = 8x²y²z²(x + y + z)

= 8(x³y²z² + x²y³z² + x²y²z³) ÷ 4x²y²z² 

= ${\displaystyle \frac{8(x^3{y}^2{z}^2+x^2{y}^3{z}^2+x^2{y}^2{z}^3)}{4x^2{y}^2{z}^2}}$

= ${\displaystyle \frac{8x^2{y}^2{z}^2(x+y+z)}{4x^2{y}^2{z}^2}}$

= 2 (x + y + z)