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प्रश्न
Draw the graph of the equation 4x - 3y + 12 = 0.
Also, find the area of the triangle formed by the line drawn and the coordinate axes.
उत्तर
4x - 3y + 12 = 0
⇒ 4x = 3y - 12
⇒ x = `(3y - 12)/(4)`
Corresponding values of x and y can be tabulated as follows :
| X | -3 | -1.5 | 0 |
| Y | 0 | 2 | 4 |
Plotting the points (-3, 0), (-1.5, 2) and (0, 4),
We get the following graph :
Area of ΔOAB = `(1)/(2)` x OB x OA
= `(1)/(2) xx 3 xx 4`
= 6 sq. units.
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