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Evaluate: |1aa2-bc1bb2-ca1cc2-ab| - Business Mathematics and Statistics

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प्रश्न

Evaluate: `|(1,a,a^2 - bc),(1,b,b^2 - ca),(1,c,c^2 - ab)|`

योग

उत्तर

`|(1,a,a^2 - bc),(1,b,b^2 - ca),(1,c,c^2 - ab)|`

= `|(1,a,a^2),(1,b,b^2),(1,c,c^2)| + |(1,a,- bc),(1,b,- ca),(1,c,- ab)|`  ...(By property 6)

= `|(1,a,a^2),(1,b,b^2),(1,c,c^2)| - |(1,a,bc),(1,b,ca),(1,c,ab)|`  ...(Take out -1 from C3)

= `|(1,a,a^2),(1,b,b^2),(1,c,c^2)| - 1/"abc" |(a,a^2,abc),(b,b^2,abc),(c,c^2,abc)|`  .....(Multiply R1 by a, R2 by b, R3 by c and divide the determinant by abc)

= `|(1,a,a^2),(1,b,b^2),(1,c,c^2)| - "abc"/"abc" |(a,a^2,1),(b,b^2,1),(c,c^2,1)|`  ....(Take out abc from C3)

= `|(1,a,a^2),(1,b,b^2),(1,c,c^2)| + |(a,1,a^2),(b,1,b^2),(c,1,c^2)|`   ..... (C2 ↔ C3)

= `|(1,a,a^2),(1,b,b^2),(1,c,c^2)| - |(1,a,a^2),(1,b,b^2),(1,c,c^2)|`   ..... (C1 ↔ C2)

= 0

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Determinants
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Matrices and Determinants - Exercise 1.1 [पृष्ठ ७]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 11 TN Board
अध्याय 1 Matrices and Determinants
Exercise 1.1 | Q 6. | पृष्ठ ७
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