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Question
Evaluate: `|(1,a,a^2 - bc),(1,b,b^2 - ca),(1,c,c^2 - ab)|`
Solution
`|(1,a,a^2 - bc),(1,b,b^2 - ca),(1,c,c^2 - ab)|`
= `|(1,a,a^2),(1,b,b^2),(1,c,c^2)| + |(1,a,- bc),(1,b,- ca),(1,c,- ab)|` ...(By property 6)
= `|(1,a,a^2),(1,b,b^2),(1,c,c^2)| - |(1,a,bc),(1,b,ca),(1,c,ab)|` ...(Take out -1 from C3)
= `|(1,a,a^2),(1,b,b^2),(1,c,c^2)| - 1/"abc" |(a,a^2,abc),(b,b^2,abc),(c,c^2,abc)|` .....(Multiply R1 by a, R2 by b, R3 by c and divide the determinant by abc)
= `|(1,a,a^2),(1,b,b^2),(1,c,c^2)| - "abc"/"abc" |(a,a^2,1),(b,b^2,1),(c,c^2,1)|` ....(Take out abc from C3)
= `|(1,a,a^2),(1,b,b^2),(1,c,c^2)| + |(a,1,a^2),(b,1,b^2),(c,1,c^2)|` ..... (C2 ↔ C3)
= `|(1,a,a^2),(1,b,b^2),(1,c,c^2)| - |(1,a,a^2),(1,b,b^2),(1,c,c^2)|` ..... (C1 ↔ C2)
= 0
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