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प्रश्न
Evaluate the definite integral:
`int_0^(pi/2) cos 2x dx`
उत्तर
`int_0^(pi/2) cos 2x "dx"`
`= [1/2 (sin 2x)]_0^(pi/2)`
`= 1/2 (sin pi - sin 0)`
`= 1/2 (0 - 0)`
= 0
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