Advertisements
Advertisements
प्रश्न
Evaluate, using (a + b)(a - b)= a2 - b2.
399 x 401
योग
उत्तर
399 x 401
= (400 - 1) x (400 + 1)
= (400)2 - (1)2
= 160000 - 1
= 159999.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise the following:
8a3 + b3 + 12a2b + 6ab2
Simplify `(a + b + c)^2 + (a - b + c)^2`
Simplify the expression:
`(x + y + z)^2 + (x + y/2 + 2/3)^2 - (x/2 + y/3 + z/4)^2`
Simplify the following expressions:
`(x + y - 2z)^2 - x^2 - y^2 - 3z^2 +4xy`
Find the following product:
(3x − 4y + 5z) (9x2 +16y2 + 25z2 + 12xy −15zx + 20yz)
If \[x - \frac{1}{x} = \frac{1}{2}\],then write the value of \[4 x^2 + \frac{4}{x^2}\]
Use the direct method to evaluate :
(4+5x) (4−5x)
If x + y = 9, xy = 20
find: x - y
Factorise the following:
9x2 + 4y2 + 16z2 + 12xy – 16yz – 24xz
Find the following product:
(x2 – 1)(x4 + x2 + 1)