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Evaluate the (Viii) ( 0 . 99 ) 5 + ( 1 . 01 ) 5 - Mathematics

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प्रश्न

Evaluate the

(viii)  \[\left( 0 . 99 \right)^5 + \left( 1 . 01 \right)^5\]

 

उत्तर

\[(0 . 99 )^5 + (1 . 01 )^5 \]
\[ = (1 - 0 . 01 )^5 + (1 + 0 . 01 )^5 \]
\[ = 2[ ^{5}{}{C}_0 (0 . 01 )^0 + ^{5}{}{C}_2 (0 . 01 )^2 + ^{5}{}{C}_4 (0 . 01 )^4 ]\]
\[ = 2[1 + 10 \times 0 . 0001 + 5 \times 0 . 00000001]\]
\[ = 2 \times 1 . 00100005 = 2 . 0020001\] 

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Introduction of Binomial Theorem
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 18: Binomial Theorem - Exercise 18.1 [पृष्ठ ११]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 18 Binomial Theorem
Exercise 18.1 | Q 2.08 | पृष्ठ ११

संबंधित प्रश्न

Using binomial theorem, write down the expansions  :

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\[= ^{5}{}{C}_0 (2x )^5 (3y )^0 +^{5}{}{C}_1 (2x )^4 (3y )^1 + ^{5}{}{C}_2 (2x )^3 (3y )^2 + ^{5}{}{C}_3 (2x )^2 (3y )^3 + ^{5}{}{C}_4 (2x )^1 (3y )^4 +^{5}{}{C}_5 (2x )^0 (3y )^5\]

\[= 32 x^5 + 5 \times 16 x^4 \times 3y + 10 \times 8 x^3 \times 9 y^2 + 10 \times 4 x^2 \times 27 y^3 + 5 \times 2x \times 81 y^4 + 243 y^5 \]
\[ = 32 x^5 + 240 x^4 y + 720 x^3 y^2 + 1080 x^2 y^3 + 810x y^4 + 243 y^5 \]

 

 


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