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Using Binomial Theorem Evaluate .(Ii) (102)5 - Mathematics

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प्रश्न

Using binomial theorem evaluate  .

(ii) (102)5

 

उत्तर

(ii) (102)5

\[= (100 + 2 )^5 \]

\[ = ^{5}{}{C}_0 \times {100}^5 \times 2^0 +^{5}{}{C}_1 \times {100}^4 \times 2^1 + ^{5}{}{C}_2 \times {100}^3 \times 2^2 + ^{5}{}{C}_3 \times {100}^2 \times 2^3 +^{5}{}{C}_4 \times {100}^1 \times 2^4 + ^{5}{}{C}_5 \times {100}^0 \times 2^5 \]

\[ = 10000000000 + 1000000000 + 40000000 + 800000 + 8000 + 32\]

\[ = 11040808032\]

 

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Introduction of Binomial Theorem
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 18: Binomial Theorem - Exercise 18.1 [पृष्ठ १२]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 18 Binomial Theorem
Exercise 18.1 | Q 5.2 | पृष्ठ १२

संबंधित प्रश्न

Using binomial theorem, write down the expansions  :

(iii)  \[\left( x - \frac{1}{x} \right)^6\]

\[= ^{5}{}{C}_0 (2x )^5 (3y )^0 +^{5}{}{C}_1 (2x )^4 (3y )^1 + ^{5}{}{C}_2 (2x )^3 (3y )^2 + ^{5}{}{C}_3 (2x )^2 (3y )^3 + ^{5}{}{C}_4 (2x )^1 (3y )^4 +^{5}{}{C}_5 (2x )^0 (3y )^5\]

\[= 32 x^5 + 5 \times 16 x^4 \times 3y + 10 \times 8 x^3 \times 9 y^2 + 10 \times 4 x^2 \times 27 y^3 + 5 \times 2x \times 81 y^4 + 243 y^5 \]
\[ = 32 x^5 + 240 x^4 y + 720 x^3 y^2 + 1080 x^2 y^3 + 810x y^4 + 243 y^5 \]

 

 


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