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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 8

Evaluate: x5+n(x2)3n+1x7n-2 - Mathematics

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प्रश्न

Evaluate:

`(x^(5+n)(x^2)^(3n+1))/x^(7n-2)`

योग

उत्तर

`(x^(5+n)(x^2)^(3n+1))/x^(7n-2)`

Step 1: Simplify `(x^2)^(3n+1)`

Using the rule (am)n = am⋅n:

(x2)3n+1 = x2(3n+1) = x6n+2.

Step 2: Multiply x5+n and x6n+2

Using the product rule (am⋅an = am+n):

x5+n⋅x6n+2 = x(5+n)+(6n+2) = x5+n+6n+2 = x7+7n.

Step 3: Divide by x7n−2

Using the quotient rule `a^m/a^n = a^(m-n)`:

`x^(7+7n)/x^(7n-2)`

`= x^((7+7n)−(7n−2))`

`= x^(7+7n−7n+2)`

`= x^(7+2)`

`= x^9`

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More About Exponents
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Exponents - Exercise 2 (B) [पृष्ठ ३४]

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सेलिना Concise Mathematics [English] Class 8 ICSE
अध्याय 2 Exponents
Exercise 2 (B) | Q 9 | पृष्ठ ३४
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