Find: (A + B)(A + B) - Mathematics

Find : (a + b)(a + b)

योग

(a + b)(a + b) = (a + b)²= a × a + a × b + b × a + b × b
= a² + ab + ab + b²= a² + b² + 2ab

shaalaa.com

Special Product

क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

अध्याय 4: Expansions (Including Substitution) - Exercise 4 (E) [पृष्ठ ६६]

अध्याय 4 Expansions (Including Substitution)
Exercise 4 (E) | Q 11.1 | पृष्ठ ६६

Simplify : ( x + 6 )( x + 4 )( x - 2 )

Simplify : ( x - 6 )( x - 4 )( x + 2 )

Simplify : ( x + 6 )( x - 4 )( x - 2 )

Simplify using following identity : `( a +- b )(a^2 +- ab + b^2) = a^3 +- b^3`
( 2x + 3y )( 4x² + 6xy + 9y²)

Simplify using following identity : `( a +- b )(a^2 +- ab + b^2) = a^3 +- b^3`
`( 3x - 5/x )( 9x^2 + 15 + 25/x^2)`

Find : (a + b)(a + b)(a + b)

Prove that : x²+ y² + z² - xy - yz - zx is always positive.

If x = 3 + 2√2, find :
(i) `1/x`

(ii) `x - 1/x`

(iii) `( x - 1/x )^3`

(iv) `x^3 - 1/x^3`

If x + 5y = 10; find the value of x³ + 125y³ + 150xy - 1000.

Using suitable identity, evaluate (97)³