Find: (A + B)(A + B) - Mathematics

Find : (a + b)(a + b)

बेरीज

(a + b)(a + b) = (a + b)²= a × a + a × b + b × a + b × b
= a² + ab + ab + b²= a² + b² + 2ab

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Special Product

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पाठ 4: Expansions (Including Substitution) - Exercise 4 (E) [पृष्ठ ६६]

पाठ 4 Expansions (Including Substitution)
Exercise 4 (E) | Q 11.1 | पृष्ठ ६६

Simplify : ( x + 6 )( x - 4 )( x - 2 )

Simplify using following identity : `( a +- b )(a^2 +- ab + b^2) = a^3 +- b^3`
( 2x + 3y )( 4x² + 6xy + 9y²)

Simplify using following identity : `( a +- b )(a^2 +- ab + b^2) = a^3 +- b^3`
`( 3x - 5/x )( 9x^2 + 15 + 25/x^2)`

Find : (a + b)(a + b)(a + b)

Prove that : x²+ y² + z² - xy - yz - zx is always positive.

If a + b = 11 and a² + b² = 65; find a³ + b³.

If x + 5y = 10; find the value of x³ + 125y³ + 150xy - 1000.

Simplify :
`[(x^2 - y^2)^3 + (y^2 - z^2)^3 + (z^2 - x^2)^3]/[(x - y)^3 + (y - z)^3 + (z - x)^3]`

Evaluate :
`[0.8 xx 0.8 xx 0.8 + 0.5 xx 0.5 xx 0.5]/[0.8 xx 0.8 - 0.8 xx 0.5 + 0.5 xx .5]`

Evaluate :
`[1.2 xx 1.2 + 1.2 xx 0.3 + 0.3 xx 0.3 ]/[ 1.2 xx 1.2 xx 1.2 - 0.3 xx 0.3 xx 0.3]`