Advertisements
Advertisements
प्रश्न
If x + 5y = 10; find the value of x3 + 125y3 + 150xy - 1000.
उत्तर
x + 5y = 10
⇒ (x + 5y)3 = 103
⇒ x3 + (5y)3 + 3(x)(5y)(x + 5y) = 1000
⇒ x3 + (5y)3 + 3(x)(5y)(10) = 1000
= x3 + (5y)3 + 150xy = 1000
= x3 + (5y)3 + 150xy - 1000 = 0
APPEARS IN
संबंधित प्रश्न
Simplify : ( x - 6 )( x - 4 )( x - 2 )
Simplify : ( x + 6 )( x - 4 )( x - 2 )
Simplify using following identity : `( a +- b )(a^2 +- ab + b^2) = a^3 +- b^3`
`(a/3 - 3b)(a^2/9 + ab + 9b^2)`
Find : (a + b)(a + b)
Find : (a + b)(a + b)(a + b)
Find : (a - b)(a - b)(a - b)
Prove that : x2+ y2 + z2 - xy - yz - zx is always positive.
If x = 3 + 2√2, find :
(i) `1/x`
(ii) `x - 1/x`
(iii) `( x - 1/x )^3`
(iv) `x^3 - 1/x^3`
If a - 2b + 3c = 0; state the value of a3 - 8b3 + 27c3.
Evaluate :
`[1.2 xx 1.2 + 1.2 xx 0.3 + 0.3 xx 0.3 ]/[ 1.2 xx 1.2 xx 1.2 - 0.3 xx 0.3 xx 0.3]`