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Find the Domain of the Real Valued Function of Real Variable: (Iv) F ( X ) = 2 X + 1 X 2 − 9 - Mathematics

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प्रश्न

Find the domain of the real valued function of real variable: 

(iv)  \[f\left( x \right) = \frac{2x + 1}{x^2 - 9}\]

 

उत्तर

(iv) Given: 

\[f\left( x \right) = \frac{2x + 1}{x^2 - 9}\]
Domain of f :
Clearly,  (x) is defined for all  x ∈ R except for x2 -9 ≠  0, i.e. x = ± 3.
At x = -3, 3,  f (x) takes the intermediate form
\[\frac{1}{0} .\]  Hence, domain ( f ) = R -{ - 3, 3 }.
 

 

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अध्याय 3: Functions - Exercise 3.3 [पृष्ठ १८]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 3 Functions
Exercise 3.3 | Q 1.4 | पृष्ठ १८

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