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Question
Find the domain of the real valued function of real variable:
(iv) \[f\left( x \right) = \frac{2x + 1}{x^2 - 9}\]
Solution
(iv) Given:
Clearly, f (x) is defined for all x ∈ R except for x2 -9 ≠ 0, i.e. x = ± 3.
At x = -3, 3, f (x) takes the intermediate form
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