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Question
Find the domain of the real valued function of real variable:
(v) \[f\left( x \right) = \frac{x^2 + 2x + 1}{x^2 - 8x + 12}\]
Solution
(v) Given:
Clearly, f (x) assumes real values for all x except for all those values of x for which x2 - 8x + 12 = 0, i.e. x = 2, 6.
Hence, domain ( f ) = R - {2,6}.
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