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Question
Find the domain of the real valued function of real variable:
(iv) \[f\left( x \right) = \frac{\sqrt{x - 2}}{3 - x}\]
Solution
(iv) Given:
Clearly, f (x) assumes real values if
x -2 ≥ 0 and 3-x > 0
⇒ x ≥ 2 and 3 > x
⇒ x ∈ [2, 3)
Hence, domain ( f ) = [2, 3) .
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