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प्रश्न
Find the equation of a line passing through the intersection of x + 3y = 6 and 2x - 3y = 12 and parallel to the line 5x + 2y = 10
उत्तर
x + 3y = 6...........(1)
2x - 3y = 12..........(2)
Adding (1) and (2), we get
3x = 18
⇒ x = 6
And y = 0
Point of intersection of given line is (6,0)
Slope of 5x + 2y = 10 is `(-5)/2`
Slope of required line is `(-5)/2`
Equation of required line is `("y" - "y"_1)/("x" - "x"_1)` = slope
`("y" - 0)/("x" - 6) = (-5)/2`
⇒ -5x + 30 = 2y
⇒ 5x + 2y - 30 = 0
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संबंधित प्रश्न
Given the equation of line L, is y = 4.
(1) Write the slope of line L2, if L2, is the bisector of angle O.
(2) Write the co–ordinates of point P.
(3) Find the equation of L2.
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Find the equation of a line which passes through (5, 4) and makes an angle of 60° with the positive direction of the x-axis.
A, B and C have co-ordinates (0, 3), (4, 4) and (8, 0) respectively. Find the equation of the line through A and perpendicular to BC.
Find the equation of the line with x-intercept 5 and a point on it (–3, 2).
A and B are two points on the x-axis and y-axis respectively. P(2, −3) is the mid point of AB. Find the
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- slope of line AB
- equation of line AB.
The vertices of a ΔABC are A(3, 8), B(–1, 2) and C(6, –6). Find:
(i) Slope of BC
(ii) Equation of a line perpendicular to BC and passing through A.
Find if the following points lie on the given line or not:
(2,4) on the line y = 2x - 1
Find the value of a line parallel to the following line:
x = `"y"/2` - 5
Given equation of line L1 is y = 4.
(i) Write the slope of line, if L2 is the bisector of angle O.
(ii) Write the coordinates of point P.
(iii) Find the equation of L2
