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Find the Modulus and Argument of the Following Complex Number and Hence Express in the Polar Form: 1 − I - Mathematics

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प्रश्न

Find the modulus and argument of the following complex number and hence express in the polar form:

1 − i

उत्तर

\[z = 1 - i \]

\[r = \left| z \right|\]

\[ = \sqrt{1 + 1}\]

\[ = \sqrt{2}\]

\[\text { Let} \tan \alpha = \left| \frac{Im\left( z \right)}{Re\left( z \right)} \right|\]

\[ \therefore \tan\alpha = \left| \frac{- 1}{1} \right|\]

\[ = \frac{\pi}{4}\]

\[ \Rightarrow \alpha = \frac{\pi}{4}\]

\[\text { Since point } (1, - 1) \text { lies in the fourth quadrant, the argument of z is given by } \]

\[\theta = - \alpha = - \frac{\pi}{4}\]

\[\text { Polar form } = r\left( \cos \theta + i\sin \theta \right) \]

\[ = \sqrt{2}\left\{ \cos\left( - \frac{\pi}{4} \right) + i\sin\left( - \frac{\pi}{4} \right) \right\}\]

\[ = \sqrt{2}\left( \cos\frac{\pi}{4} - i\sin\frac{\pi}{4} \right)\]

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अध्याय 13: Complex Numbers - Exercise 13.4 [पृष्ठ ५७]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 13 Complex Numbers
Exercise 13.4 | Q 1.3 | पृष्ठ ५७

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