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प्रश्न
Find the nature of roots of the following quadratic equations:
`12x^2-4sqrt15x+5=0`
उत्तर
The given equation is `12x^2-4sqrt15+5=0`
This is of the form `ax^2+bx+c=0` where `a=5, b=-10 and c=6`
∴Discriminant, `D=b^2-4ac=(-4sqrt15)^2-4xx12xx5=240-240=0`
Hence, the given equation has real and equal roots.
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Relationship Between Discriminant and Nature of Roots
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