Advertisements
Advertisements
प्रश्न
Find the area of the following triangle:
उत्तर
Area of triangle = `1/2 xx "Base" xx "Height"`
Base = 5 cm,
Height = 3.2 cm
Area = `1/2 xx 5 xx 3.2`
= 8 cm2
APPEARS IN
संबंधित प्रश्न
Prove that the area of a triangle with vertices (t, t −2), (t + 2, t + 2) and (t + 3, t) is independent of t.
Find the area of the triangle formed by joining the mid-point of the sides of the triangle whose vertices are (0, –1), (2, 1) and (0, 3). Find the ratio of area of the triangle formed to the area of the given triangle.
Find a relation between x and y if the points (x, y), (1, 2) and (7, 0) are collinear.
Find the centre of a circle passing through the points (6, − 6), (3, − 7) and (3, 3).
If A(–5, 7), B(–4, –5), C(–1, –6) and D(4, 5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD
A field is in the shape of a right angled triangle whose base is 25 m and height 20 m. Find the cost of levelling the field at the rate of ₹ 45 per sq.m2
Let ∆ = `|("A"x, x^2, 1),("B"y, y^2, 1),("C"z, z^2, 1)|`and ∆1 = `|("A", "B", "C"),(x, y, z),(zy, zx, xy)|`, then ______.
Points A(–6, 10), B(–4, 6) and C(3, –8) are collinear such that AB = `2/9` AC.
The area of ∆ABC is 8 cm2 in which AB = AC = 4 cm and ∠A = 90º.
The base and the corresponding altitude of a parallelogram are 10 cm and 3.5 cm, respectively. The area of the parallelogram is 30 cm2.