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Find the coordinates of the foci and the vertices, the eccentricity, and the length of the latus rectum of the hyperbola. 16x2 – 9y2 = 576 - Mathematics

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प्रश्न

Find the coordinates of the foci and the vertices, the eccentricity, and the length of the latus rectum of the hyperbola.

16x2 – 9y2 = 576

योग

उत्तर

Equation of hyperbola: 16x2 – 9y2 = 576

On dividing by 576,

`x^2/36 - y^2/64 = 1`

The transverse axis is along the x-axis.

a2 = 36, b2 = 64

∴ c2 = a2 + b2 = 36 + 64 = 100

∴ a = 6, b = 8, c = 10

The coordinates of the vertices are (±a, 0) or (±6, 0)

The coordinates of the foci are (±c, 0) or (±10, 0)

Eccentricity e = `c/a = 10/6 = 5/3`

Length of the latus rectum = `(2b^2)/a`

= `(2xx 64)/6`

= `64/3`

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अध्याय 11: Conic Sections - Exercise 11.4 [पृष्ठ २६२]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 11 Conic Sections
Exercise 11.4 | Q 4 | पृष्ठ २६२

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