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Find the coordinates of the foci and the vertices, the eccentricity, and the length of the latus rectum of the hyperbola. x216-y29=1 - Mathematics

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प्रश्न

Find the coordinates of the foci and the vertices, the eccentricity, and the length of the latus rectum of the hyperbola.

`x^2/16 - y^2/9 = 1`

योग

उत्तर

Equation of hyperbola `x^2/16 - y^2/9 = 1`

The transverse axis is along the x-axis.

a2 = 16, b2 = 9

∴ c2 = a2 + b2 = 16 + 9 = 25

∴ a = 4, b = 3, c = 5

The coordinates of the vertices are (± a, 0) or (± 4, 0)

The coordinates of the foci are (± c, 0) or (± 5, 0)

Eccentricity = e = `c/a = 5/4`

length of the latus rectum = `(2b^2)/a = (2 xx 9)/4 = 9/2`

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अध्याय 11: Conic Sections - Exercise 11.4 [पृष्ठ २६२]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 11 Conic Sections
Exercise 11.4 | Q 1 | पृष्ठ २६२

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