Advertisements
Advertisements
प्रश्न
Find the equation of the line, whose x-intercept = −4 and y-intercept = 6
उत्तर
When x-intercept = −4, corresponding point on x-axis is (−4, 0)
When y-intercept = 6, corresponding point on y-axis is (0, 6).
Let (x1, y1) = (−4, 0) and (x2, y2) = (0, 6)
Slope = `(6 - 0)/(0 + 4) = (6)/4 =3/2`
The required equation is:
y – y1 = m(x – x1)
`y - 0 = (3)/2(x + 4)`
2y = 3x + 12
APPEARS IN
संबंधित प्रश्न
State, true or false :
The point (8, 7) lies on the line y – 7 = 0
The line segment joining the points (5, −4) and (2, 2) is divided by the points Q in the ratio 1 : 2. Does the line x – 2y = 0 contain Q?
The co-ordinates of two points P and Q are (2, 6) and (−3, 5) respectively Find the co-ordinates of the point where PQ intersects the x-axis.
The vertices of a ΔABC are A(3, 8), B(–1, 2) and C(6, –6). Find:
(i) Slope of BC
(ii) Equation of a line perpendicular to BC and passing through A.
Find if the following points lie on the given line or not:
(7, -2) on the line 5x + 7y = 11
Find the value of a line parallel to the following line:
x = `"y"/2` - 5
Find the equation of a line whose slope and y-intercept are m = `2/3`, c = -2
Find the equation of a line whose slope and y-intercept are m = -3, c = -1
Find the equation of a line passing through the intersection of x + 3y = 6 and 2x - 3y = 12 and parallel to the line 5x + 2y = 10
Find the equation of the straight line perpendicular to 5x – 2y = 8 and which passes through the mid-point of the line segment joining (2, 3) and (4, 5).