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प्रश्न
Find the equation of the line, whose x-intercept = 5 and y-intercept = 3
उत्तर
When x-intercept = 5, corresponding point on x-axis is (5, 0)
When y-intercept = 3, corresponding point on y-axis is (0, 3).
Let (x1, y1) = (5, 0) and (x2, y2) = (0, 3)
Slope = `(3 - 0)/(0 - 5) = (-3)/5`
The required equation is:
y – y1 = m(x – x1)
`y - 0 = (-3)/5(x - 5)`
5y = –3x + 15
3x + 5y = 15
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