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प्रश्न
Find the equation of the line, whose x-intercept = −8 and y-intercept = −4
उत्तर
When x-intercept = −8, corresponding point on x-axis is (−8, 0)
When y-intercept = −4, corresponding point on y-axis is (0, −4).
Let (x1, y1) = (−8, 0) and (x2, y2) = (0, −4)
Slope = `(-4 - 0)/(0 + 8) = (-4)/8 = (-1)/2`
The required equation is:
y − y1 = m(x − x1)
`y - 0 = (-1)/2(x + 8)`
2y = −x − 8
x + 2y + 8 = 0
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