Advertisements
Advertisements
प्रश्न
Find the value of discriminant.
x2 + 7x – 1 = 0
उत्तर
x2 + 7x - 1 = 0
Comparing the given equation with ax2 + bx + c = 0
a = 1, b = 7, c = -1
b2 - 4ac = (7)2 - 4(1)(-1)
= 49 + 4
= 53
APPEARS IN
संबंधित प्रश्न
Solve for x:
`16/x-1=15/(x+1);x!=0,-1`
Find the roots of the following quadratic equations, if they exist, by the method of completing the square 2x2 + x – 4 = 0
Find the roots of the following quadratic equations, if they exist, by the method of completing the square 2x2 + x + 4 = 0
Find the roots of the quadratic equations 2x2 + x – 4 = 0 by applying the quadratic formula.
Two taps running together can fill a tank in `3 1/13` hours. If one tap takes 3 hours more than the other to fill the tank, then how much time will each tap take to fill the tank?
Find the roots of the following quadratic equations (if they exist) by the method of completing the square.
`x^2-4sqrt2x+6=0`
`3x^2-2x-1=0`
`4x^2+4bx-(a^2-b^2)=0`
`x^2-(sqrt2+1)x+sqrt2=0`
The sum of the areas of two squares is `640m^2` . If the difference in their perimeter be 64m, find the sides of the two square
Sum of the areas of two squares is 400 cm2. If the difference of their perimeters is 16 cm, find the sides of the two squares ?
Solve the following quadratic equation by completing the square method.
x2 + x – 20 = 0
Solve the following quadratic equation by completing the square method.
m2 – 5m = –3
Solve the following quadratic equation by completing the square method.
2y2 + 9y + 10 = 0
Fill in the gaps and complete.
Determine the nature of roots of the following quadratic equation.
m2 + 2m + 9 = 0
Sum of the area of two squares is 400 cm2. If the difference of their perimeters is 16 cm, find the sides of two squares.
The value of \[\sqrt{6 + \sqrt{6 + \sqrt{6 +}}} . . . .\] is
A chess board contains 64 equal squares and the area of each square is 6.25 cm2. A border round the board is 2 cm wide. The length of the side of the chess board is:
A rectangular field has an area of 3 sq. units. The length is one more than twice the breadth ‘x’. Frame an equation to represent this.
