Advertisements
Advertisements
प्रश्न
Find the value of :
sin 690°
उत्तर
sin 690° = sin (720° – 30°)
= sin (2 x 360° – 30°)
= – sin 30°
= `(-1)/2`
APPEARS IN
संबंधित प्रश्न
Find the value of:
sin 15°
Find the values of:
tan 105°
Find the values of:
cot 225°
Find the value of :
sin (495°)
Find the value of :
cos (600°)
Find the value of :
tan 225°
Find the value of :
cosec 780°
Find the value of :
cot (– 1110°)
Prove the following:
sec 840° . cot (– 945°) + sin 600° tan (– 690°) = `3/2`
Prove the following:
`(sin^3(pi + x)sec^2(pi - x)tan(2pi - x))/(cos^2(pi/2 + x)sin(pi - x)"cosec"^2 - x)` = tan3x
Select the correct option from the given alternatives :
If sin θ = n sin (θ + 2α), then tan (θ + α) is equal to
Prove the following:
cosec 48° + cosec 96° + cosec 192° + cosec 384° = 0
Prove the following:
sin 18° = `(sqrt(5) - 1)/4`
Prove the following:
`tan pi/8 = sqrt(2) - 1`
If a = sin 175°+ cos 175°, then ______.
If θ = `(17π)/3` then, tan θ – cot θ = ______.
`(1 - 2[cos 60^circ - cos 80^circ])/(2 sin 10^circ)` = ______.
The value of sin 495° is ______.
The value of `cos π/8 + cos (3π)/8 + cos (5π)/8 + cos (7π)/8` is ______.
The value of `2 cot^2(π/6) + 4 tan^2(π/6) - 3 "cosec"(π/6)` is ______.
Find the value of `cos ((29 π)/3)`.
The value of `(cot 54^circ)/(tan 36^circ) + (tan 20^circ)/(cot 70^circ)` is ______.
The value of cos 480° sin 150° + sin 600° cos 390° is ______.
The value of `cos^2 π/16 + cos^2 (3π)/16 + cos^2 (5π)/16 + cos^2 (7π)/16` is ______.
If tan θ = `1/sqrt(7)`, then `(("cosec"^2θ - sec^2θ))/(("cosec"^2θ + sec^2θ))` is equal to ______.
cos 1° + cos 2° + cos 3° + ... + cos 180° is equal to ______.
If ΔABC is a right angled at C, then tan A + tan B is equal to ______.
If sin A + sin B + sin C = 3, then cos A + cos B + cos C is equal to ______.
The value of sin 930° is ______.
The value of cos(– 870°) is ______.
The value of sin 135° cosec 225° tan 150° cot 315° is ______.
sin (270° – θ) sin (90° – θ) – cos ( 270° – θ) cos (90° + θ) is ______.
