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Find the vector equation of line passing through the point having position vector ijk5i^+4j^+3k^ and having direction ratios –3, 4, 2. - Mathematics and Statistics

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प्रश्न

Find the vector equation of line passing through the point having position vector `5hat"i" + 4hat"j" + 3hat"k"` and having direction ratios  –3, 4, 2.

योग

उत्तर

Let A be the point whose position vector is a = `5hat"i" + 4hat"j" + 3hat"k"`.

Let `bar"b"` be the vector parallel to the line having direction ratio = –3, 4, 2

Then, `bar"b" = -3hat"i" + 4hat"j" + 2hat"k"`

The vector equation of the line passing through `"A"(bara)` and parallel to `bar"b"  "is"  bar"r" = bar"a" + lambdabar"b"`, where λ is a scalar.

∴ The required vector equation of the line is `bar"r" = 5hat"i" + 4hat"j" + 3hat"k" + lambda(-3hat"i" + 4hat"j" + 2hat"k").`

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Vector and Cartesian Equations of a Line
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Line and Plane - Exercise 6.1 [पृष्ठ २००]

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