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प्रश्न
Find the value of the following:
\[\left( \frac{1}{2} \right)^{- 1} + \left( \frac{1}{3} \right)^{- 1} + \left( \frac{1}{4} \right)^{- 1}\]
योग
उत्तर
\[\left( \frac{1}{2} \right)^{- 1} + \left( \frac{1}{3} \right)^{- 1} + \left( \frac{1}{4} \right)^{- 1} = \frac{1}{1/2} + \frac{1}{1/3} + \frac{1}{1/4}\] → (a−1 = 1/a)
=2+3+4
=12
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