Advertisements
Advertisements
प्रश्न
Find the value of a line parallel to the following line:
`(3"y")/4 + (5"y")/2 = 7`
उत्तर
`(3"y")/4 + (5"y")/2 = 7`
10y = -3x + 28
y = `-3/10"x" + 14/5`
m1 = `-3/10`
Slope of required line (m2) = m1 = `-3/10`
APPEARS IN
संबंधित प्रश्न
Find, which of the following points lie on the line x – 2y + 5 = 0 :
(–5, 0)
The line given by the equation `2x - y/3 = 7` passes through the point (k, 6); calculate the value of k.
The line y = 3x – 2 bisects the join of (a, 3) and (2, −5), find the value of a.
Find the equation of a line whose : y-intercept = −1 and inclination = 45°
Find the equation of the line passing through : (−1, −4) and (3, 0)
Find the equations of the line through (1, 3) and making an intercept of 5 on the y-axis.
A line intersects x-axis at point (−2, 0) and cuts off an intercept of 3 units from the positive side of y-axis. Find the equation of the line.
Given equation of line L1 is y = 4.
- Write the slope of line L2 if L2 is the bisector of angle O.
- Write the co-ordinates of point P.
- Find the equation of L2.
Find if the following points lie on the given line or not:
(5,3) on the line 3x - 5y + 5 = 0
Find the equation of a line whose slope and y-intercept are m = -3, c = -1
