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प्रश्न
Given equation of line L1 is y = 4.
- Write the slope of line L2 if L2 is the bisector of angle O.
- Write the co-ordinates of point P.
- Find the equation of L2.
उत्तर
i. Equation of line L1 is y = 4
∵ L2 is the bisector of ∠O
∴ ∠POX = 45°
Slope = tan 45° = 1 ...(i)
Let coordinates of P be (x, y)
∵ P lies on L1
ii. ∴ Slope of L2 = `(y_2 - y_1)/(x_2 -x_1)`
`1 = (4 - 0)/(x - 0)`
`=> 1 = 4/x` ...(ii)
From equation (i) and (ii)
`1 = 4/x`
`=>` x = 4
∴ Coordinates of P are (4, 4)
iii. Equation of L2 is
y – y1 = m(x – x1)
`=>` y – 4 = 1(x – 4)
`=>` y – 4 = x – 4
`=>` x = y
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