Advertisements
Advertisements
प्रश्न
Find:
- equation of AB
- equation of CD
उत्तर
i. Slope of AB = `(3 - 4)/(3 - (-5)) = -1/8`
∴ Equation of AB is given by
`y - 4 = -1/8(x - (-5))`
8y – 32 = –(x + 5)
8y – 32 = –x – 5
x + 8y = 27
ii. AB and CD are perpendicular to each other.
Thus, product of their slope = –1
Slope of AB × Slope of CD = –1
`=>` Slope of CD = 8
Now, from graph we have coordinates of D = (–3, 0)
∴ Equation of line CD is given by
y – y1 = m(x – x1)
y – 0 = 8(x – 3)
y = 8(x + 3)
y = 8x + 24
APPEARS IN
संबंधित प्रश्न
If (4,-3) is a point on the line AB and slope of the line is (-2), write the equation of the line AB.
In ΔABC, A(3, 5), B(7, 8) and C(1, –10). Find the equation of the median through A.
Is the line 3x + 2y = 5 parallel to the line x + 2y = 1?
B(−5, 6) and D(1, 4) are the vertices of rhombus ABCD. Find the equations of diagonals BD and AC.
Show that points P(2, –2), Q(7, 3), R(11, –1) and S (6, –6) are vertices of a parallelogram.
In Δ DEF, line PQ || side EF, If DP = 2.4,
PE = 7.2, DQ = 1 then find QF.
In the figure, line PQ || line RS. Using the information given
in the figure find the value of x.
Find Equation of CD
A straight line passes through the points P(–1, 4) and Q(5, –2). It intersects x-axis at point A and y-axis at point B. M is the mid-point of the line segment AB. Find:
- the equation of the line.
- the co-ordinates of point A and B.
- the co-ordinates of point M.
Find the equation of line through the intersection of lines 2x – y = 1 and 3x + 2y = –9 and making an angle of 30° with positive direction of x-axis.