Advertisements
Advertisements
प्रश्न
Grouped frequency distribution of supply of milk to hotels and the number of hotels is given in the following table. Find the mode of the supply of milk.
Milk (Litre) | 1 - 3 | 3 - 5 | 5 - 7 | 7 - 9 | 9 - 11 | 11 - 13 |
No. of hotels | 7 | 5 | 15 | 20 | 35 | 18 |
उत्तर
The maximum class frequency is 35.
The class corresponding to this frequency is 9 - 11.
So, the modal class is 9 - 11.
L (the lower limit of modal class) = 9
f1 (frequency of the modal class) = 35
fo (frequency of the class preceding the modal class) = 20
f2 (frequency of the class succeeding the modal class) = 18
h (class size) = 2
Mode = \[L + \left( \frac{f_1 - f_0}{2 f_1 - f_0 - f_2} \right) \times h\]
\[= 9 + \left( \frac{35 - 20}{2 \times 35 - 20 - 18} \right) \times 2\]
= 9 + 0.9375
= 9.9375 ≈ 9.94
Hence, the mode of the supply of milk is 9.94 litres.
APPEARS IN
संबंधित प्रश्न
100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:
Number of letters | Number of surnames |
1 - 4 | 6 |
4 − 7 | 30 |
7 - 10 | 40 |
10 - 13 | 6 |
13 - 16 | 4 |
16 − 19 | 4 |
Determine the median number of letters in the surnames. Find the mean number of letters in the surnames? Also, find the modal size of the surnames.
The following is the distribution of the size of certain farms from a taluka (tehasil):
Size of Farms (in acres) |
Number of Farms |
5 – 15 | 7 |
15 – 25 | 12 |
25 – 35 | 17 |
35 – 45 | 25 |
45 – 55 | 31 |
55 – 65 | 5 |
65 – 75 | 3 |
Find median size of farms.
Calculate the median from the following data:
Marks below: | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 |
No. of students: | 15 | 35 | 60 | 84 | 96 | 127 | 198 | 250 |
An incomplete distribution is given below:
Variable: | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |
Frequency: | 12 | 30 | - | 65 | - | 25 | 18 |
You are given that the median value is 46 and the total number of items is 230.
(i) Using the median formula fill up missing frequencies.
(ii) Calculate the AM of the completed distribution.
The following table shows the daily wages of workers in a factory:
Daily wages in (Rs) | 0 – 100 | 100 – 200 | 200 – 300 | 300 – 400 | 400 – 500 |
Number of workers | 40 | 32 | 48 | 22 | 8 |
Find the median daily wage income of the workers.
Given below is the number of units of electricity consumed in a week in a certain locality:
Class | 65 – 85 | 85 – 105 | 105 – 125 | 125 – 145 | 145 – 165 | 165 – 185 | 185 – 200 |
Frequency | 4 | 5 | 13 | 20 | 14 | 7 | 4 |
Calculate the median.
In the following data the median of the runs scored by 60 top batsmen of the world in one-day international cricket matches is 5000. Find the missing frequencies x and y.
Runs scored | 2500 – 3500 | 3500 – 4500 | 4500 – 5500 | 5500 – 6500 | 6500 – 7500 | 7500 - 8500 |
Number of batsman | 5 | x | y | 12 | 6 | 2 |
Find the median wages for the following frequency distribution:
Wages per day (in Rs) | 61 – 70 | 71 – 80 | 81 – 90 | 91 – 100 | 101 – 110 | 111 – 120 |
No. of women workers | 5 | 15 | 20 | 30 | 20 | 8 |
The following table shows the information regarding the milk collected from farmers on a milk collection centre and the content of fat in the milk, measured by a lactometer. Find the mode of fat content.
Content of fat (%) | 2 - 3 | 3 - 4 | 4 - 5 | 5 - 6 | 6 - 7 |
Milk collected (Litre) | 30 | 70 | 80 | 60 | 20 |
The following frequency distribution table gives the ages of 200 patients treated in a hospital in a week. Find the mode of ages of the patients.
Age (years) | Less than 5 | 5 - 9 | 10 - 14 | 15 - 19 | 20 - 24 | 25 - 29 |
No. of patients | 38 | 32 | 50 | 36 | 24 | 20 |
Find the correct answer from the alternatives given.
Distance Covered per litre (km) | 12 - 14 | 14 - 16 | 16 - 18 | 18 - 20 |
No. of cars | 11 | 12 | 20 | 7 |
The median of the distances covered per litre shown in the above data is in the group . . . . . .
The median of the following data is 50. Find the values of p and q, if the sum of all the frequencies is 90.
Marks: | 20 -30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 |
Frequency: | P | 15 | 25 | 20 | q | 8 | 10 |
The annual rainfall record of a city for 66 days is given in the following table :
Rainfall (in cm ): | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 |
Number of days : | 22 | 10 | 8 | 15 | 5 | 6 |
Calculate the median rainfall using ogives of more than type and less than type.
If the mean of the following distribution is 3, find the value of p.
x | 1 | 2 | 3 | 5 | p + 4 |
f | 9 | 6 | 9 | 3 | 6 |
In a hospital, weights of new born babies were recorded, for one month. Data is as shown:
Weight of new born baby (in kg) | 1.4 - 1.8 | 1.8 - 2.2 | 2.2 - 2.6 | 2.6 - 3.0 |
No of babies | 3 | 15 | 6 | 1 |
Then the median weight is?
Pocket expenses of a class in a college are shown in the following frequency distribution:
Pocket expenses |
0 - 200 |
200 - 400 |
400 - 600 |
600 - 800 |
800 - 1000 |
1000 - 1200 |
1200 - 1400 |
Number of students | 33 | 74 | 170 | 88 | 76 | 44 | 25 |
Then the median for the above data is?
The abscissa of the point of intersection of the less than type and of the more than type cumulative frequency curves of a grouped data gives its ______.
The median of the following data is 525. Find the values of x and y, if the total frequency is 100.
Class interval | Frequency |
0 – 100 | 2 |
100 – 200 | 5 |
200 – 300 | x |
300 – 400 | 12 |
400 – 500 | 17 |
500 – 600 | 20 |
600 – 700 | y |
700 – 800 | 9 |
800 – 900 | 7 |
900 – 1000 | 4 |
The median of the following frequency distribution is 35. Find the value of x.
Class: | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 |
Frequency: | 6 | 3 | x | 12 | 19 |
Consider the following frequency distribution:
Class | 0 – 6 | 6 – 12 | 12 – 18 | 18 – 24 | 24 – 30 |
Frequency | 12 | 10 | 15 | 8 | 11 |
The median class is: