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If [ 3 → a + 7 → B → C → D ] = λ [ → a → C → D ] + μ [ → B → C → D ] , Then Find the Value of λ + μ. - Mathematics

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प्रश्न

If \[\left[ 3 \vec{a} + 7 \vec{b} \vec{c} \vec{d} \right] = \lambda\left[ \vec{a} \vec{c} \vec{d} \right] + \mu\left[ \vec{b} \vec{c} \vec{d} \right],\] then find the value of λ + μ.

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उत्तर

We have

\[\left[ 3 \vec{a} + 7 \vec{b} \vec{c} \vec{d} \right] = \lambda \left[ \vec{a} \vec{c} \vec{d} \right] + \mu\left[ \vec{b} \vec{c} \vec{d} \right]\]

\[ \Rightarrow \left[ \left( 3 \vec{a} + 7 \vec{b} \right) \times \vec{c} \right] . \vec{d} = \lambda \left[ \vec{a} \vec{c} \vec{d} \right] + \mu\left[ \vec{b} \vec{c} \vec{d} \right] \left(\text {  By definition of scalar triple product } \right)\]

\[ \Rightarrow \left[ \left( 3 \vec{a} \times \vec{c} \right) + \left( 7 \vec{b} \times \vec{c} \right) \right] . \vec{d} = \lambda \left[ \vec{a} \vec{c} \vec{d} \right] + \mu\left[ \vec{b} \vec{c} \vec{d} \right] \]

\[ \Rightarrow \left( 3 \vec{a} \times \vec{c} \right) . \vec{d} + \left( 7 \vec{b} \times \vec{c} \right) . \vec{d} = \lambda \left[ \vec{a} \vec{c} \vec{d} \right] + \mu\left[ \vec{b} \vec{c} \vec{d} \right] \]

\[ \Rightarrow \left[ 3 \vec{a} \vec{c} \vec{d} \right] + \left[ 7 \vec{b} \vec{c} \vec{d} \right] = \lambda \left[ \vec{a} \vec{c} \vec{d} \right] + \mu\left[ \vec{b} \vec{c} \vec{d} \right]\]

\[ \Rightarrow 3 \left[ \vec{a} \vec{c} \vec{d} \right] + 7 \left[ \vec{b} \vec{c} \vec{d} \right] = \lambda \left[ \vec{a} \vec{c} \vec{d} \right] + \mu\left[ \vec{b} \vec{c} \vec{d} \right] \left( \because \left[ \lambda \vec{a} \vec{b} \vec{c} \right] = \lambda\left[ \vec{a} \vec{b} \vec{c} \right] \text { for any scalar } \lambda \right)\]

Comparing both sides, we get

\[\lambda = 3 \]

\[\mu = 7\]

\[ \therefore \lambda + \mu = 3 + 7 = 10\]

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अध्याय 26: Scalar Triple Product - Exercise 26.1 [पृष्ठ १८]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 26 Scalar Triple Product
Exercise 26.1 | Q 9 | पृष्ठ १८

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