Advertisements
Advertisements
प्रश्न
If 3x - `4/x` = 4; and x ≠ 0 find : 27x3 - `64/x^3`
उत्तर
3x - `4/x` = 4;
We need to find 27x3 - `64/x^3`
Let us now consider the expansion of `( 3x - 4/x )^3` :
`( 3x - 4/x )^3 = 27x^3 - 64/x^3 - 3 xx 3x xx 4/x( 3x - 4/x )`
⇒ `(4)^3 = 27x^3 - 64/x^3 - 144 ["Given :" 3x - 4/x = 4]`
⇒ 64 + 144 = 27x3 - `64/x^3`
⇒ 27x3 - `64/x^3` = 208
APPEARS IN
संबंधित प्रश्न
Expand : ( x + 8 ) ( x + 10 )
Expand : ( x + 8 )( x - 10 )
Expand : `( 3a + 2/b )( 2a - 3/b )`
Expand : ( x + y - z )2
Expand : ( 5a - 3b + c )2
If a + `1/a` = m and a ≠ 0 ; find in terms of 'm'; the value of :
`a - 1/a`
If x > 0 and `x^2 + 1/[9x^2] = 25/36, "Find" x^3 + 1/[27x^3]`
If 2( x2 + 1 ) = 5x, find :
(i) `x - 1/x`
(ii) `x^3 - 1/x^3`
Find the value of 'a': 4x2 + ax + 9 = (2x + 3)2
The sum of two numbers is 7 and the sum of their cubes is 133, find the sum of their square.