Advertisements
Advertisements
प्रश्न
If the perimeter of the circle is 8π units and centre is (2, 2) then the equation of the circle is:
विकल्प
(x – 2)2 + (y – 2)2 = 4
(x – 2)2 + (y – 2)2 = 16
(x – 4)2 + (y – 4)2 = 16
x2 + y2 = 4
उत्तर
(x – 4)2 + (y – 4)2 = 16
APPEARS IN
संबंधित प्रश्न
Find the centre and radius of the circle
x2 + y2 = 16
Find the centre and radius of the circle.
5x2 + 5y2+ 4x – 8y – 16 = 0
If the lines x + y = 6 and x + 2y = 4 are diameters of the circle, and the circle passes through the point (2, 6) then find its equation.
Find the Cartesian equation of the circle whose parametric equations are x = 3 cos θ, y = 3 sin θ, 0 ≤ θ ≤ 2π.
If (4, 1) is one extremity of a diameter of the circle x2 + y2 - 2x + 6y - 15 = 0 find the other extremity.
(1, -2) is the centre of the circle x2 + y2 + ax + by – 4 = 0, then its radius:
The equation of the circle with centre on the x axis and passing through the origin is:
Find the equation of circles that touch both the axes and pass through (− 4, −2) in general form
Find centre and radius of the following circles
x2 + y2 + 6x – 4y + 4 = 0
Find centre and radius of the following circles
x2 + y2 – x + 2y – 3 = 0