Advertisements
Advertisements
प्रश्न
In the equation of the circle x2 + y2 = 16 then v intercept is (are):
विकल्प
4
16
± 4
± 16
उत्तर
± 4
APPEARS IN
संबंधित प्रश्न
If the lines x + y = 6 and x + 2y = 4 are diameters of the circle, and the circle passes through the point (2, 6) then find its equation.
Find the Cartesian equation of the circle whose parametric equations are x = 3 cos θ, y = 3 sin θ, 0 ≤ θ ≤ 2π.
Find the equation of the tangent to the circle x2 + y2 – 4x + 4y – 8 = 0 at (-2, -2).
Determine whether the points P(1, 0), Q(2, 1) and R(2, 3) lie outside the circle, on the circle or inside the circle x2 + y2 – 4x – 6y + 9 = 0.
Find the value of P if the line 3x + 4y – P = 0 is a tangent to the circle x2 + y2 = 16.
The centre of the circle x2 + y2 – 2x + 2y – 9 = 0 is:
If the circle touches the x-axis, y-axis, and the line x = 6 then the length of the diameter of the circle is:
Find centre and radius of the following circles
2x2 + 2y2 – 6x + 4y + 2 = 0
Choose the correct alternative:
If the normals of the parabola y2 = 4x drawn at the end points of its latus rectum are tangents to the circle (x – 3)2 + (y + 2)2 = r2, then the value of r2 is
Choose the correct alternative:
Let C be the circle with centre at (1, 1) and radius = 1. If T is the circle centered at (0, y) passing through the origin and touching the circle C externally, then the radius of T is equal to