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प्रश्न
Determine whether the points P(1, 0), Q(2, 1) and R(2, 3) lie outside the circle, on the circle or inside the circle x2 + y2 – 4x – 6y + 9 = 0.
उत्तर
The equation of the circle is x2 + y2 – 4x – 6y + 9 = 0
`"PT"^2 = x_1^2 + y_1^2 - 4x_1 - 6y_1 + 9`
At P(1, 0), PT2 = 1 + 0 – 4 – 0 + 9 = 6 > 0
At Q(2, 1), PT2 = 4 + 1 – 8 – 6 + 9 = 0
At R(2, 3), PT2 = 4 + 9 – 8 – 18 + 9 = -4 < 0
The point P lies outside the circle.
The point Q lies on the circle.
The point R lies inside the circle.
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संबंधित प्रश्न
Find the centre and radius of the circle
x2 + y2 = 16
Find the centre and radius of the circle.
5x2 + 5y2+ 4x – 8y – 16 = 0
Find the equation of the circle on the line joining the points (1, 0), (0, 1), and having its centre on the line x + y = 1.
Find the length of the tangent from (1, 2) to the circle x2 + y2 – 2x + 4y + 9 = 0.
Find the values of a and b if the equation (a - 1)x2 + by2 + (b - 8)xy + 4x + 4y - 1 = 0 represents a circle.
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If the perimeter of the circle is 8π units and centre is (2, 2) then the equation of the circle is:
Find the equation of the tangent and normal to the circle x2 + y2 – 6x + 6y – 8 = 0 at (2, 2)
Choose the correct alternative:
The equation of the normal to the circle x2 + y2 – 2x – 2y + 1 = 0 which is parallel to the line 2x + 4y = 3 is