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प्रश्न
If y = 2 + log x, then show that xy2 + y1 = 0.
योग
उत्तर
y = 2 + log x
`y_1 = 0 +1/x`
i.e., `y_1 = 1/x`
`therefore y_2 = - 1/x^2`
Now `xy_2 + y_1 = x(- 1/x^2) + 1/x = (-1)/x + 1/x = 0`
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