Advertisements
Advertisements
प्रश्न
In a hexagon JKLMNO, side JK || ON and ∠K : ∠L : ∠M : ∠N = 6 : 5 : 4 : 3. Find the angle ∠K and ∠M.
उत्तर
Given JK || ON
⇒ ∠J + ∠O = 180°
Also, ∠K : ∠L : ∠M : ∠N = 6 : 5 : 4 : 3
⇒ ∠K = 6x, ∠L = 5x, ∠M = 4x and ∠N = 3x
Since, ∠J + ∠K + ∠L + ∠M +∠N = 4 x 180°
⇒ (∠J + ∠O) +∠K + ∠L + ∠M + ∠N = 4 x 180°
⇒180° + 6x + 5x + 4x + 3x = 720°
⇒ 18x + 180° = 720°
⇒18x = 540°
⇒ x = 30°
Hence,
∠K = 6x
= 6 x 30°
= 180°
and
∠M = 4x
= 4 x 30°
= 120°.
APPEARS IN
संबंधित प्रश्न
In a pentagon ABCDE, AB is parallel to DC and ∠A: ∠E : ∠D = 3: 4: 5. Find angle E.
In a parallelogram ABCD, AB = 20 cm and AD = 12 cm. The bisector of angle A meets DC at E and BC produced at F.
Find the length of CF.
Find each exterior angle of a regular polygon of: 9 sides
Find each exterior angle of a regular polygon of: 15 sides
Find the number of sides in a regular polygon, when each exterior angle is: 72°
Is it possible to have a polygon whose each interior angle is 124°?
If the difference between an exterior angle of a regular polygon of 'n' sides and an exterior angle of another regular polygon of '(n + 1)' sides is equal to 4°; find the value of 'n'.
The number of sides of two regular polygons are in the ratio 2 : 3 and their interior angles are in the ratio 9 : 10. Find the number of sides of each polygon.
Find the value of each angle of an octagon if four of its angles are equal and the other four are each greater than these by 20°.
The number angle of a regular polygon is double the exterior angle. Find the number of sides of the polygon.