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In a quadrilateral ABCD, ∠A = 72° and ∠C is the supplementary of ∠A. The other two angles are 2x – 10 and x + 4. Find the value of x and the measure of all the angles - Mathematics

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प्रश्न

In a quadrilateral ABCD, ∠A = 72° and ∠C is the supplementary of ∠A. The other two angles are 2x – 10 and x + 4. Find the value of x and the measure of all the angles

योग

उत्तर


∠A = 72°

∠C = 180° – 12° ...(∠A and ∠C are supplementary)

= 108°

∠A + ∠B + ∠C + ∠D = 360° ...(Total angles of quadrilateral)

72° + 2x – 10 + 108° + x + 4 = 360°

3x + 174° = 360°

x = `(186^circ)/3`

= 62°

The value of x is 62°

∠B = 2x – 10

= 2(62°) – 10

= 124° – 10°

= 114°

∠D = x + 4

= 62° + 4

= 66°

The other angles are 114°, 62° and 66°.

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अध्याय 4: Geometry - Exercise 4.2 [पृष्ठ १५७]

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सामाचीर कलवी Mathematics [English] Class 9 TN Board
अध्याय 4 Geometry
Exercise 4.2 | Q 2 | पृष्ठ १५७
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