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ABCD is a rectangle whose diagonals AC and BD intersect at O. If ∠OAB = 46°, find ∠OBC - Mathematics

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प्रश्न

ABCD is a rectangle whose diagonals AC and BD intersect at O. If ∠OAB = 46°, find ∠OBC

योग

उत्तर

Since the diagonals of a rectangle AC and BD are equal and bisect each other

∴ OA = OB

∠OAB = ∠OBA = 46°

Each angle of a rectangle measures 90°

∠ABC = 90°

∠ABO + ∠OBC = 90°

46° + ∠OBC = 90°

∠OBC = 90° − 46°

∴ ∠OBC = 44°

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अध्याय 4: Geometry - Exercise 4.2 [पृष्ठ १५७]

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सामाचीर कलवी Mathematics [English] Class 9 TN Board
अध्याय 4 Geometry
Exercise 4.2 | Q 3 | पृष्ठ १५७
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