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In a Series, Lcr Circuit, Obtain an Expression for the Resonant Frequency, - Physics (Theory)

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प्रश्न

In a series, LCR circuit, obtain an expression for the resonant frequency,

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उत्तर

In a series LCR circuit,

`I=E/sqrt(R^2+(ωL-1/(ωc))^2`

From this equation, we may observe that when ω=0, I become O, and again when 

ω = ∞, I = 0

∴ This implies there must be a value of ω at which I is maximum.

So when I is maximum, `sqrt(R^2+(ωL-1/(ωc))^2` is minimum 

For this either R = 0, or ωL -` 1/(ωc) =0`

So when ωL -`1/(ωc)=0`,  this is called resonance condition.

∴ At resonance,

             ωL`=1/(ωc)`

⇒      `ω^2 =1/(Lc)`

⇒      `ω_r  = 1/sqrt(Lc)`

⇒    `2pif_r = 1/sqrt(Lc)`

∴        `f_r` = Frequency of resonance

              `=1/(2pi). 1/sqrt(Lc)`

i.e.,     `f_r =1/(2pi) . 1/sqrt(Lc)`

This is the required experssion for resonant frequency.

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2016-2017 (March)

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