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In δAbc, P is the Mid-point of Bc. a Line Through P and Parallel to Ca Meets Ab at Point Q, and a Line Through Q and Parallel to Bc Meets Median Ap at Point R. Prove That: Ap = 2ar - Mathematics

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प्रश्न

In ΔABC, P is the mid-point of BC. A line through P and parallel to CA meets AB at point Q, and a line through Q and parallel to BC meets median AP at point R. Prove that: AP = 2AR

योग

उत्तर


In ΔABC,
P is the mid-point of BC and PQ is parallel to AC
Therefore, Q is the mid-point of AB.
In ΔABP,
Q is the mid-point of AB and QR is parallel to BP
Therefore, R is the mid-point of AP.
AR = RP
But AR + RP = AP
⇒ AR + AR = AP
⇒ 2AR = AP or AP = 2AR.

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अध्याय 15: Mid-point and Intercept Theorems - Exercise 15.1

APPEARS IN

फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 15 Mid-point and Intercept Theorems
Exercise 15.1 | Q 16.1

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