Advertisements
Advertisements
प्रश्न
In ∆ABC, point M is the midpoint of side BC. If, AB2 + AC2 = 290 cm2, AM = 8 cm, find BC.
उत्तर
In ∆ABC, point M is the midpoint of side BC.
AB2 + AC2 = 2AM2 + 2BM2 ...[by Apollonius theorem]
290 = 2 (8)2 + 2BM2
290 = 2 (64) + 2BM2
290 = 128 + 2BM2
2BM2 = 290 - 128
2BM2 = 162
BM2 = 81
BM = `sqrt81`
BM = 9 cm
Point M is the midpoint of BC
∴ BC = 2BM = 2 × 9
∴ BC = 18 cm.
संबंधित प्रश्न
Adjacent sides of a parallelogram are 11 cm and 17 cm. If the length of one of its diagonal is 26 cm, find the length of the other.
In the given figure, seg PS is the median of ∆PQR and PT ⊥ QR. Prove that,
PR2 = PS2 + QR × ST + `("QR"/2)^2`
Some question and their alternative answer are given.
In a right-angled triangle, if sum of the squares of the sides making right angle is 169 then what is the length of the hypotenuse?
Height and base of a right angled triangle are 24 cm and 18 cm find the length of its hypotenuse
Some question and their alternative answer are given. Select the correct alternative.
In ∆ABC, AB = \[6\sqrt{3}\] cm, AC = 12 cm, BC = 6 cm. Find measure of ∠A.
In ∆ABC, seg AP is a median. If BC = 18, AB2 + AC2 = 260, Find AP.
Sum of the squares of adjacent sides of a parallelogram is 130 sq.cm and length of one of its diagonals is 14 cm. Find the length of the other diagonal.
Seg PM is a median of ∆PQR. If PQ = 40, PR = 42 and PM = 29, find QR.
Seg AM is a median of ∆ABC. If AB = 22, AC = 34, BC = 24, find AM
Choose the correct alternative:
Out of the following which is a Pythagorean triplet?
In ΔPQR, seg PM is the median. If PM = 9, PQ2 + PR2 = 290, Find QR.
In ΔABC, seg AP is a median. If BC = 18, AB2 + AC2 = 260, then find the length of AP.
Choose the correct alternative:
Out of given triplets, which is not a Pythagoras triplet?
Choose the correct alternative:
Out of all numbers from given dates, which is a Pythagoras triplet?
"The diagonals bisect each other at right angles." In which of the following quadrilaterals is the given property observed?
