Question

In Figure, assuming the diodes to be ideal ______.

विकल्प

• D₁ is forward biased and D₂ is reverse biased and hence current flows from A to B.

• D₂ is forward biased and D₁ is reverse biased and hence no current flows from B to A and vice versa.

• D₁ and D₂ are both forward biased and hence current flows from A to B.

• D₁ and D₂ are both reverse biased and hence no current flows from A to B and vice versa.

Answer 1

In Figure, assuming the diodes to be ideal D₂ is forward biased and D₁ is reverse biased and hence no current flows from B to A and vice versa.

Explanation:

A symbol of the diode is represented like this: In this problem first, we have to check the polarity of the diodes. –10 V is the lower voltage in the circuit. Now p-side of p-n Anode Cathode junction D₁ is connected to lower voltage and n-side of D₁ to the higher voltage. Thus D₁ is reverse biased.

Now, let us analyse 2^nd diode of the given circuit. The p-side of p-n junction D₂ is at higher potential and n-side of D₂ is at lower potential. Therefore D₂ is forward biased.

Hence, the current flows through the junction from B to A.