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In a Horizontal Line Through Its Base, the Elevation of Its Top Changes from 30° to 60°. the Height of the Chimney is - Mathematics

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प्रश्न

It is found that on walking x meters towards a chimney in a horizontal line through its base, the elevation of its top changes from 30° to 60°. The height of the chimney is

विकल्प

  • \[3\sqrt{2}x\]

  • \[2\sqrt{3}x\]

  • \[\frac{\sqrt{3}}{2}x\]

  • \[\frac{2}{\sqrt{3}}x\]

MCQ

उत्तर

Let h be the height of chimney AB 

Given that: angle of elevation changes from angle `∠D=30°`to .`∠C=60°`

Then Distance becomes `CD=x` and we assume `BC=y`

Here, we have to find the height of chimeny.

So we use trigonometric ratios.

In a triangle,ABC

`⇒ tan C=(AB)/(BC)` 

`⇒ tan 60°=(AB)/(BC)` 

`⇒ sqrt3=h/y`

`⇒y=h/sqrt3`

Again in a triangle ABD, 

`⇒ tan D=(AB)/(BC+CD)`

`⇒ tan 30°=h/(y+x)`

`⇒1/sqrt3=h/(y+x)` 

`⇒sqrt3h=y+x`

`⇒sqrt3h=h/sqrt3+x`                           `["put" y=h/sqrt3]`

`⇒ h(sqrt3-1/sqrt3)=x`

`⇒h=x/(sqrt3-1/sqrt3)`

`⇒h=(sqrt3x)/2`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Trigonometry - Exercise 12.3 [पृष्ठ ४३]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 12 Trigonometry
Exercise 12.3 | Q 16 | पृष्ठ ४३

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